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GATE2013-8
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
edited
Nov 4, 2020
by
soujanyareddy13
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Human genome sequencing project involved the construction of genomic library in
bacterial artificial chromosome
$pBR322$
bacteriophage
$pcDNA3.1$
gate2013
human-dna
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
edited
Nov 4, 2020
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soujanyareddy13
by
Milicevic3306
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Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
GATE2013-52
A DNA fragment of 5000bp needs to be isolated from $E.coli$ (genome size $4\times10^3 kb$) genomic library. The minimum number of independent recombinant clones required to represent this fragment in genomic library are $16\times10^2$ $12\times10^2$ $8\times10^2$ $1.25\times10^2$
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
by
Milicevic3306
7.9k
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gate2013
ristriction-enzyme-plasmid
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Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
GATE2013-42
A complete restriction digestion of a circular plasmid $(5000bp)$ was carried out with $HindIII,BamHIandEcoRIindividually.$ Restriction digestion yielded following fragments. $Plasmid + HindIII \rightarrow 1200bp\: and\: 3800bp$ $Plasmid + BamHI \rightarrow 5000bp$ ... $EcoRl-3, BamHI-2, HindIII-1$ $EcoRI-2, BamHI-2, HindIII-1$
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
by
Milicevic3306
7.9k
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gate2013
restriction
plasmid
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Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
GATE2013-16
The suitable substitution matrix to align closely related sequences is $\text{PAM 250 or BLOSSUM 80}$ $\text{PAM 40 or BLOSSUM 80}$ $\text{PAM 120 or BLOSSUM 40}$ $\text{PAM 250 or BLOSSUM 40}$
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
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Milicevic3306
7.9k
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gate2013
matrix
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Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
GATE2013-15
The $RNA$ primer synthesized during the replication process in bacteria is removed by $DNA$ gyrase primase $DNA$ polymerase $I$ $DNA$ polymerase $II$
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
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Milicevic3306
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gate2013
polymerase
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Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
GATE2013-14
Of the two diploid species, species $I$ has $36$ chromosomes and species $II$ has $28$ chromosomes. How many chromosomes would be found in an allotriploid individual? $42$ or $54 $ $46$ or $50 $ $74$ or $86 $ $84$ or $108$
Milicevic3306
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Recombinant DNA technology and Other Tools in Biotechnology
Mar 26, 2018
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Milicevic3306
7.9k
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gate2013
chromosome
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