0 votes 0 votes The Laplace transform of $f(t) = 2t + 6$ is $\frac{1}{s}+\frac{2}{s^2}$ $\frac{3}{s}-\frac{6}{s^2}$ $\frac{6}{s}+\frac{2}{s^2}$ $-\frac{6}{s}+\frac{2}{s^2}$ Differential Equations gate2013 differential-equations laplace-transforms + – Milicevic3306 asked Mar 25, 2018 • retagged Mar 18, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer comment Share Follow See all 0 reply Please log in or register to add a comment.