# GATE2013-49

A solution was prepared by dissolving $\text{100 mg}$ of protein $X$ in $\text{100 ml}$ of water. Molecular weight of protein $X$ is $\text{15,000 Da};$ Avogadro’s number = $6.022\times 10^{23}$.
1. $40.15\times10^{19}$
2. $6.023\times10^{19}$
3. $4.015\times10^{19}$
4. $0.08\times10^{19}$