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Operators $\square$, $\lozenge$ and $\rightarrow$ are defined by: $a \: \square \: b = \dfrac{a-b}{a+b}$; $a \: \lozenge \: b = \dfrac{a+b}{a-b}$; $a \rightarrow b = ab$. Find the value of $(66 \: \square \: 6) \rightarrow (66 \: \lozenge \: 6)$.

  1. $-2$
  2. $-1$
  3. $1$
  4. $2$
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