0 votes 0 votes The solution to $\frac {dy}{dx}+y \cot x=\csc x$ is $y=(c+x)\cot x$ $y=(c+x)\csc x$ $y=(c+x)\csc x\cot x$ $y=(c+x)\frac{\csc x}{\cot x}$ Differential Equations gate2013 differential-equations + – Milicevic3306 asked Mar 25, 2018 • edited Mar 18, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer comment Share Follow See all 0 reply Please log in or register to add a comment.