0 votes 0 votes The solution of the differential equation $\frac{d y}{d x}=y+e^{-x}$ that satisfies $y(0)=-\frac{1}{2}$ is $\_\_\_\_\_\_\_$. $-\frac{1}{2} e^{-\frac{x}{2}}$ $-\frac{1}{2} e^{x}$ $-\frac{1}{2} e^{-x}$ $-\frac{1}{2} e^{\frac{x}{2}}$ Others gatebt-2024 + – admin asked Mar 25 • edited Mar 27 by makhdoom ghaya admin 2.7k points answer comment Share Follow See all 0 reply Please log in or register to add a comment.