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GATE2013-18
0
votes
If $u=log (e^x+e^y),$ then $\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}=$
$e^x+e^y$
$e^x-e^y$
$\frac{1}{e^x+e^y}$
$1$
gate2013
continuity-and-defferentiability
asked
Mar 26, 2018
in
Linear Algebra
Milicevic3306
7.9k
points
edited
Nov 4, 2020
by
soujanyareddy13
answer
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