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Recent questions tagged partial-derivatives

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GATE2013-18
If $u=\log (e^x+e^y),$ then $\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}=$ $e^x+e^y$ $e^x-e^y$ $\frac{1}{e^x+e^y}$ $1$
If $u=\log (e^x+e^y),$ then $\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}=$$e^x+e^y$$e^x-e^y$$\frac{1}{e^x+e^y}$$1$
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