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GATE2013-41
Milicevic3306
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Differential Equations
Mar 26, 2018
edited
Mar 18, 2021
by
Lakshman Patel RJIT
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The solution to $\frac {dy}{dx}+y \cot x=\csc x$ is
$y=(c+x)\cot x$
$y=(c+x)\csc x$
$y=(c+x)\csc x\cot x$
$y=(c+x)\frac{\csc x}{\cot x}$
gate2013
differential-equations
Milicevic3306
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Differential Equations
Mar 26, 2018
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