GATE2013-41

Milicevic3306 asked in Differential Equations Mar 26, 2018 edited Mar 18, 2021 by Lakshman Patel RJIT

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The solution to $\frac {dy}{dx}+y \cot x=\csc x$ is

$y=(c+x)\cot x$
$y=(c+x)\csc x$
$y=(c+x)\csc x\cot x$
$y=(c+x)\frac{\csc x}{\cot x}$

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differential-equations

Milicevic3306 asked in Differential Equations Mar 26, 2018 edited Mar 18, 2021 by Lakshman Patel RJIT

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