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GATE2013-41
0
votes
The solution to $\frac {dy}{dx}+y \cot x=cosec\;x$ is
$y=(c+x)\cot x$
$y=(c+x)cosec\;x$
$y=(c+x)cosec\;x\cot x$
$y=(c+x)\frac{cosec\;x}{\cot x}$
gate2013
continuity-and-defferentiability
asked
Mar 26, 2018
in
Linear Algebra
Milicevic3306
7.9k
points
edited
Nov 5, 2020
by
soujanyareddy13
answer
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