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GATE2013-41

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The solution to $\frac {dy}{dx}+y \cot x=cosec\;x$ is

  1. $y=(c+x)\cot x$
  2. $y=(c+x)cosec\;x$
  3. $y=(c+x)cosec\;x\cot x$
  4. $y=(c+x)\frac{cosec\;x}{\cot x}$
in Linear Algebra 7.9k points
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