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The solution to $\frac {dy}{dx}+y \cot x=\csc x$ is

  1. $y=(c+x)\cot x$
  2. $y=(c+x)\csc x$
  3. $y=(c+x)\csc x\cot x$
  4. $y=(c+x)\frac{\csc x}{\cot x}$
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