0 votes 0 votes What is the solution of the differential equation $\dfrac{\mathrm{dy} }{\mathrm{d} x}=\dfrac{x}{y}$, with the initial condition, at $x=0, y=1?$ $x^{2}=y^{2}+1$ $y^{2}=x^{2}+1$ $y^{2}=2x^{2}+1$ $x^{2}-y^{2}=0$ Others gate2019 differential-equations + – soujanyareddy13 asked Nov 3, 2020 • retagged Mar 18, 2021 by Lakshman Bhaiya soujanyareddy13 2.7k points answer comment Share Follow See all 0 reply Please log in or register to add a comment.