0 votes 0 votes Let $y(x)=x^2 \ln x$ for $x>0$, be a solution of $x^2 \frac{d^2 y}{d x^2}+4 y=\alpha x \frac{d y}{d x}$. Then the value of $\alpha$ is $\_\_\_\_\_\_\_\_\_$. Others gatebt-2024 + – admin asked Mar 25 • edited Mar 28 by makhdoom ghaya admin 2.7k points answer comment Share Follow See all 0 reply Please log in or register to add a comment.