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Questions without answers in Differential Equations
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GATE2016-24
The Laplace transform $F(s)$ of the function $f(t) = \cos (at)$, where $a$ is constant, _________ $\dfrac{s^2}{s^2+a^2} \\$ $\dfrac{a}{s^2+a^2} \\$ $\dfrac{s}{s^2+a^2} \\$ $\dfrac{s}{s^2-a^2} $
The Laplace transform $F(s)$ of the function $f(t) = \cos (at)$, where $a$ is constant, _________$\dfrac{s^2}{s^2+a^2} \\$$\dfrac{a}{s^2+a^2} \\$$\dfrac{s}{s^2+a^2} \\$$\...
Milicevic3306
7.9k
points
Milicevic3306
asked
Mar 26, 2018
Differential Equations
gate2016
differential-equations
laplace-transforms
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–
0
votes
0
answers
2
GATE2016-53
$\dfrac{d^2y}{dx^2}-y=0$. The conditions for this second order homogeneous differential equation are $y(0)=1$ and $\dfrac{dy}{dx}=3$ at $x=0$. The value of $y$ when $x = 2$ is __________
$\dfrac{d^2y}{dx^2}-y=0$. The conditions for this second order homogeneous differential equation are $y(0)=1$ and $\dfrac{dy}{dx}=3$ at $x=0$. The value of $y$ when $x = ...
Milicevic3306
7.9k
points
Milicevic3306
asked
Mar 26, 2018
Differential Equations
gate2016
numerical-answers
differential-equations
+
–
0
votes
0
answers
3
GATE2017-16
For $y=f(x)$, if $\dfrac{d^2y}{dx^2}=0$, $\dfrac{dy}{dx}=0$ at $x=0$, and $y=1$ at $x=1$, the value of $y$ at $x=2$ is __________
For $y=f(x)$, if $\dfrac{d^2y}{dx^2}=0$, $\dfrac{dy}{dx}=0$ at $x=0$, and $y=1$ at $x=1$, the value of $y$ at $x=2$ is __________
Milicevic3306
7.9k
points
Milicevic3306
asked
Mar 26, 2018
Differential Equations
gate2017
differential-equations
numerical-answers
+
–
0
votes
0
answers
4
GATE2013-41
The solution to $\frac {dy}{dx}+y \cot x=\csc x$ is $y=(c+x)\cot x$ $y=(c+x)\csc x$ $y=(c+x)\csc x\cot x$ $y=(c+x)\frac{\csc x}{\cot x}$
The solution to $\frac {dy}{dx}+y \cot x=\csc x$ is$y=(c+x)\cot x$$y=(c+x)\csc x$$y=(c+x)\csc x\cot x$$y=(c+x)\frac{\csc x}{\cot x}$
Milicevic3306
7.9k
points
Milicevic3306
asked
Mar 25, 2018
Differential Equations
gate2013
differential-equations
+
–
0
votes
0
answers
5
GATE2013-39
The Laplace transform of $f(t) = 2t + 6$ is $\frac{1}{s}+\frac{2}{s^2}$ $\frac{3}{s}-\frac{6}{s^2}$ $\frac{6}{s}+\frac{2}{s^2}$ $-\frac{6}{s}+\frac{2}{s^2}$
The Laplace transform of $f(t) = 2t + 6$ is$\frac{1}{s}+\frac{2}{s^2}$$\frac{3}{s}-\frac{6}{s^2}$$\frac{6}{s}+\frac{2}{s^2}$$-\frac{6}{s}+\frac{2}{s^2}$
Milicevic3306
7.9k
points
Milicevic3306
asked
Mar 25, 2018
Differential Equations
gate2013
differential-equations
laplace-transforms
+
–
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