in Linear Algebra recategorized by
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The solution for the following set of equations is,

$$5x+4y+102=13$$

$$x+3y+z=7$$

$$4x2y+z=0$$

  1. $x=2,y=1,z=1$
  2. $x=1,y=2,z=0$
  3. $x=1,y=0,z=2$
  4. $x=0,y=1,z=2$
in Linear Algebra recategorized by
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