0 0 votes We have $2$ rectangular sheets of paper, $M$ and $N$, of dimensions $6$ cm $\times$ $1$ cm each. Sheet $M$ is rolled to form an open cylinder by bringing the short edges of the sheet together. Sheet $N$ is cut into equal square patches and assembled to form the largest possible closed cube. Assuming the ends of the cylinder are closed, the ratio of the volume of the cylinder to that of the cube is _____________ $\frac{\pi}{2}\\$ $\frac{3}{\pi} \\$ $\frac{9}{\pi} \\$ $3 \pi$ Quantitative Aptitude gatebt-2021 numerical-ability mensuration + – go_editor 1.4k points answer comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes 2πr = 6r = 3/πCylinder volume:V₁ = πr²h= π × (3/π)² × 1= π × 9/π²= 9/πNow sheet N area = 6 cm²To make largest closed cube → 6 equal squaresEach square area = 1 cm² → side = 1 cmCube volume:V₂ = 1Ratio (Cylinder : Cube):9/π : 1 = 9/π kp6602 answered Feb 22 kp6602 240 points comment Share ask related question Follow 0 reply Please log in or register to add a comment.