2 2 votes If two distinct non-zero real variables $x$ and $y$ are such that $(x+y)$ is proportional to $(x-y)$ then the value of $\frac{x}{y}$ depends on $x y$ depends only on $x$ and not on $y$ depends only on $y$ and not on $x$ is a constant Analytical Aptitude gatebt-2024 quantitative-aptitude analytical-aptitude + – admin 3.0k points answer comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote It is given that $(x+y)$ and $(x-y)$ are proportional to each other. let the proportionality constant be $(x+y) = k(x-y)$ be $k$ Now after re-arranging them we would get. $\frac{x}{y}= \frac{(k+1)}{(k-1)}$ Therefore option $\boxed{D}$ is correct. rhl answered Aug 20, 2025 rhl 710 points comment Share ask related question Follow 0 reply Please log in or register to add a comment.