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GATE BT 2022 | Question: 5
The binding free energy of a ligand to its receptor protein is $-11.5 \; \text{kJ mol}^{-1}$ at $300 \; \text{K.}$ What is the value of the equilibrium binding constant? Use $\text{R = 8.314 J mol}^{-1} \text{K}^{-1}.$ $0.01$ $1.0$ $4.6$ $100.5$
The binding free energy of a ligand to its receptor protein is $-11.5 \; \text{kJ mol}^{-1}$ at $300 \; \text{K.}$ What is the value of the equilibrium binding constant?U...