0 0 votes Let $m$ and $n$ be fixed real numbers. If the function $y(t)=C_{1} e^{t}+C_{2} e^{-t}$ is a solution of $$ \frac{d^{2} y}{d t^{2}}+m \frac{d y}{d t}+n y=0$$ for any constants $C_{1}$ and $C_{2}$, then $m+n$ is equal to $-2$ $-1$ $0$ $1$ Differential Equations gatebt-2025 differential-equations calculus + – Shubham Sharma 2 1.4k points answer comment Share Follow 0 reply Please log in or register to add a comment.