In a fermentation process, each mole of glucose is converted to biomass $\left(\mathrm{CH}_{1.8} \mathrm{O}_{0.5} \mathrm{~N}_{0.2}\right)$, with a biomass yield coefficient of $0.4 \mathrm{C}-\mathrm{mol} / \mathrm{C}-\mathrm{mol}$, according to the unbalanced equation given below.
$$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+\mathrm{NH}_{3}+\mathrm{O}_{2} \rightarrow \mathrm{CH}_{1.8} \mathrm{O}_{0.5} \mathrm{~N}_{0.2}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O}$$
The moles of oxygen consumption per mole of glucose consumed during fermentation is $\_\_\_\_\_$
(Round off to two decimal places)
