0 0 votes Let $y(t)$ be a bacterial population whose growth is given by $$ \frac{d y}{d t}=\lambda(y+2) $$ where $\lambda$ is the growth rate constant. If $y(0)=1$ and $y(1)=4$, then the value of $\lambda$ is $\ln 2$ $\ln 3$ $\ln 4$ $\ln 6$ Differential Equations gatebt-2025 numerical-answers differential-equations microbial-growth bioreaction-engineering + – Shubham Sharma 2 1.4k points answer comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes A ANAangara answered Feb 4 ANAangara 540 points comment Share ask related question Follow 0 reply Please log in or register to add a comment.