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GATE BT 2013 | Question: 49

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A solution was prepared by dissolving $\text{100 mg}$ of protein $X$ in $\text{100 ml}$ of water. Molecular weight of protein $X$ is $\text{15,000 Da};$ Avogadro’s number = $6.022\times 10^{23}$.

The number of molecules present in this solution is

  1. $40.15\times10^{19}$
  2. $6.023\times10^{19}$
  3. $4.015\times10^{19}$
  4. $0.08\times10^{19}$

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