0 0 votes A DNA fragment of $5000bp$ needs to be isolated from E.coli (genome size $4\times10^3kb$) genomic library. The number of clones to represent this fragment in genomic library with a probability of $95\%$ are $5.9\times10^3$ $4.5\times10^3$ $3.6\times10^3$ $2.4\times10^3$ Molecular Biology and Genetics: gate2013 molecular-biology-and-genetics bioinformatics probability-and-statistics dna + – Milicevic3306 7.9k points answer comment Share Follow 0 reply Please log in or register to add a comment.