In an assay of the type II dehydroquinase of molecular mass $18$ kDa, it is found that the $V_{\text{max}}$ of the enzyme is $0.0134 \: \mu \text{ mol} \cdot \text{min}^{-1}$ when $1.8 \: \mu g$ enzyme is added to the assay mixture. If the $K_m$ for the substrate is $25 \: \mu M$, the $k_{\text{cat}}/K_m$ ratio will be _______ $\times 10^4 \: M^{-1} \cdot s^{-1}$